Question

How do you condense `log_3 (9xy^2)-log_3 (27xy)`?

Answer 1

`log_3(1/3 y)`

Explanation:

Using the `color(blue)"law of logarithms"`

`color(orange)"Reminder"`

`color(red)(|bar(ul(color(white)(a/a)color(black)(loga-logb=log(a/b))color(white)(a/a)|)))`

`rArrlog_3(9xy^2)-log_3(27xy)=log_3((9xy^2)/(27xy))`

which then simplifies to `log_3(y/3)`