How do you condense $1/2 log_2 (x^4 )+ 1/4 log_2(x^4) - 1/6 log_2 x$ ?

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Answer 1 · 2016-03-16T09:39:35

$17/6 log_2 x$

Use $log (a^mb^n)=m log a + n logb$

The expression = $log_2 x^(4/2 + 4/4 - 1/6)$ .

$= log_2x^(17/6)= 17/6 log_2x$ .

How do you condense 1/2 log_2 (x^4 )+ 1/4 log_2(x^4) - 1/6 log_2 x 1/2 log_2 (x^4 )+ 1/4 log_2(x^4) - 1/6 log_2 x?