How do you calculate $log 32$ $log32$ ?

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Answer 1 · 2016-08-07T11:37:25

$log 32 \approx 1.50515$ $log 32 ~~ 1.50515$

The approximation $log (2) \approx 0.30103$ $log(2) ~~ 0.30103$ is very good. The true value is closer to $0.301029995664$ $0.301029995664$ .

So using a common property of logs, we find:

$log 32 = {log 2}^{5} = 5 log 2 \approx 5 \cdot 0.30103 = 1.50515$ $log 32 = log 2^5 = 5 log 2 ~~ 5*0.30103 = 1.50515$

How do you calculate $log 2$ $log 2$ ?

How do you calculate log32log32log32?