How do you condense $log (5 x) + log (2 x)$ ?

Question

1687 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-03-22T20:08:46

$log(5x)+log(2x)$ $=log (10x^2)$

$log(5x)+log(2x)$
$=log(5x*2x)$ -> use property $log_bx+log_by=log_b(xy)$
$=log (10x^2)$

How do you condense log (5 x) + log (2 x)log (5 x) + log (2 x)?