Question

How do you calculate the antilog of 2?

Answer 1

antilog(2)`=100`

Explanation:

(Remember that the default base for `log` is `10`)

If `log(a)=b`
then `"antilog"(b)=a`

We are asked for `a="antilog"(2)`

So we are looking for the value `a` for which
`color(white)("XXX")log(a)=2`

By definition of `log`
`color(white)("XXX")log(a)=2`
means
`color(white)("XXX")10^2=a`

`rArr a=100`