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How do you calculate the antilog of 2?

1 Answer

Jun 12, 2016

antilog(2) $= 100$ $=100$

Explanation:

(Remember that the default base for $log$ $log$ is $10$ $10$ )

If $log (a) = b$ $log(a)=b$
then $antilog (b) = a$ $"antilog"(b)=a$

We are asked for $a = antilog (2)$ $a="antilog"(2)$

So we are looking for the value $a$ $a$ for which
$XXX log (a) = 2$ $color(white)("XXX")log(a)=2$

By definition of $log$ $log$
$XXX log (a) = 2$ $color(white)("XXX")log(a)=2$
means
$XXX 10^{2} = a$ $color(white)("XXX")10^2=a$

$\Rightarrow a = 100$ $rArr a=100$

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