How do you calculate ${log}_{2} 128$ $log_2 128$ ?

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Answer 1 · 2016-06-11T08:01:03

${log}_{2} 128 = 7$ $log_2 128 = 7$

There are 2 formats which are interchangeable:

Log form and index form.

$a^{b} = c \Rightarrow {log}_{a} c = b$ $a^b = c " " rArr log_a c = b$

In log form, ask the question..."to what power must 2 be raised to get 128?"

Knowing the powers of 2 is a huge advantage.
$128 = 2^{7}$ $128 = 2^7$

${log}_{2} 128 = 7$ $log_2 128 = 7$

How do you calculate log2128log_2 128?