How do you simplify $log5(x + 4) -log5(x + 1)$ ?

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Answer 1 · 2015-09-01T22:29:08

I got as far as: $log[(x+4)/(x+1)]$

I would use the fact that:
$logx-logy=log(x/y)$ to get:
$log5(x+4)-log5(x+1)=log[(cancel(5)(x+4))/(cancel(5)(x+1))]=log[(x+4)/(x+1)]$

How do you simplify log5(x + 4) -log5(x + 1)log5(x + 4) -log5(x + 1)?