Question

How do you condense `6log(x)-log(17)` to a simple logarithm?

Answer 1

`log(x^6/17)`

Explanation:

There are some laws of logarithms. One of them is the powers of logarithms. For instance, if we have the function `f(x)= log_a(b^c)` , then we can rewrite this as `f(x)=clog_a(b)`. Since we are trying to condense the expression into a single logarithm, `6log(x)` is equal to `log(x^6)`. Another law of logarithms is if we have the expression `log_a(b)-log_a(c)`, we can rewrite this as `log_a(b/c)`. So `log(x^6)-log(17)=log(x^6/17)`