Question

How do you condense `logA - 2logB + 3logC`?

Answer 1

`log((AC^3)/B^2)`

Explanation:

`"using the "color(blue)"laws of logarithms"`

`•color(white)(x)logx^nhArrnlogx`

`•color(white)(x)logx+logyhArrlog(xy)`

`•color(white)(x)logx-logyhArrlog(x/y)`

`rArrlogA-logB^2+logC^3`

`=log(A/B^2)+logC^3`

`=log((AC^3)/B^2)`