How do you condense 3log2t13log2u+4log2v?

1 Answer
Mar 23, 2016

log2(t3v43u)

Explanation:

As bases are common and we can condense

3log2t13log2u+4log2v, using following identities

alogxb=logxba, 1alogxb=logxb1a=logxab

logxp+logxq=logxpq and

logxplogxq=logx(pq).

Hence, 3log2t13log2u+4log2v

= log2t3log23u+log2v4

= log2(t3v43u)