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How do you condense $\frac{1}{2} {log}_{b} 3 + \frac{1}{2} {log}_{b} x - 3 {log}_{b} Z$ $1/2 Log_ b3 +1/2 Log_bx - 3 Log_b Z$ ?

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Apr 2, 2016

$= {log}_{b} 3^{\frac{1}{2}} + {log}_{b} x^{\frac{1}{2}} - {log}_{b} z^{3} = {log}_{b} (\frac{3^{\frac{1}{2}} \times x^{\frac{1}{2}}}{z^{3}})$ $=log_b3^(1/2)+log_bx^(1/2)-log_bz^3=log_b((3^(1/2)xxx^(1/2))/z^3)$

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