How do you evaluate $2 log_2 2 + log_2 8$ ?

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Answer 1 · 2016-03-22T17:32:47

$2log_2 2+log_2 8=5$

$2log_2 2+log_2 8$
$=2log_2 2+log_2 2^3$
$=2log_2 2+3 log_2 2$ ->use property $log_bx^n=n*log_bx$
$=2(1)+3(1)$ -> use property $log_b b=1$
$=5$

How do you evaluate 2 log_2 2 + log_2 82 log_2 2 + log_2 8?