How do you express log_7 3 in terms of common logarithms?

1 Answer
Oct 22, 2016

=>y=log_(10)3/log_(10)7

Explanation:

let y=log_(7)3

=>7^y=3

Take logs to base 10 both sides

log_(10)7^y=log_(10)3

=>ylog_(10)7=log_(10)3

=>y=log_(10)3/log_(10)7