How do you expand $log_3 48$ ?

Question

1939 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-09-04T12:25:15

$log_3 48 = 1+4 log_3 2$

Note that $48 = 3*2^4$

So: $log_3 48 = log_3 (3*2^4) = log_3 3 + log_3 (2^4) = 1+4 log_3 2$

How do you expand log_3 48log_3 48?