Question

How do you find the value of `log_(1/2) 15` using the change of base formula?

Answer 1

`log_(1/2)15=-3.9073`

Explanation:

`log_ab=logb/loga`

Hence, `log_(1/2)15`

= `log15/log(1/2)`

= `log15/(log1-log2)`

= `log15/(0-log2)`

= `1.1761/(-0.3010)=-3.9073`