How do you solve $5+log(2x+1)=6$ ?

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Answer 1 · 2016-07-16T18:56:21

$x = 4 1/2$

When working with equations which contain logs, each term must be a log term. We cannot work with a mixture of logs and numbers.

$5+log(2x+1)=6$

$log(2x+1)=6 -5$

$log(2x+1)=1$

$log(2x+1)=log 10" if" log A = log B, " then " A = B$

$2x+1 = 10$

$2x = 9 rArr " " x = 4 1/2$

How do you solve 5+log(2x+1)=65+log(2x+1)=6?