How do you condense $log(x+2)-log(x+5)$ ?

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Answer 1 · 2016-07-16T15:39:36

$log((x+2)/(x+5))$

Since $log a-log b= log (a/b)$

you can write

$log(x+2)-log(x+5)=log((x+2)/(x+5))$

How do you condense log(x+2)-log(x+5)log(x+2)-log(x+5)?