How do you graph $y = {log}_{4} (x) - 3$ $y = log _4 (x) - 3$ ?

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Answer 1 · 2016-05-27T09:57:03

The graph of y vs log x on a semi-log graph paper will be a straight line with slope $\frac{1}{log 4}$ $1/log 4$ . with y-interceot = $- 3$ $-3$ .

Use log_4 x= log x/log 4.

Here, $y = {log}_{4} x - 3 = \frac{log x}{log 4} - 3$ $y = log_4 x-3=log x/log 4-3$ .

y is a linear function of X = log x..

If X-graduation is in the logarithmic scale

( 1 for log 10, 2 for log 100, ..., n for ${log 10}^{n}$ $log 10^n$ ),

the graph paper is semi-logarithmic.

On this graph paper, the graph for the given equation will be a

straight line, with $\frac{1}{log 4} = 1.661$ $1/log 4 = 1.661$ , nearly, with y-intercept $= - 3$ $= -3$ .

How do you graph y=log4(x)−3y = log _4 (x) - 3?