How do you solve $y = 2 log (x)$ $y= 2 log(x)$ ?

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Answer 1 · 2018-03-18T12:21:57

$x = \sqrt{10^{y}}$ $x=sqrt(10^y)$

$y = 2 log x or y = {log x}^{2}; [{log x}^{m} = m log x]$ $y= 2log x or y= log x^2; [log x^m=mlogx]$

$:. x^2=10^y :. x=sqrt(10^y );$

$[log _b (N)=x$ , then $b^x=N]$

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How do you solve y= 2 log(x)y=2log(x)y= 2 log(x)?