How do you find the value of $\frac{1}{5} - (\frac{20 (81 \div 9)}{25})$ $1/5 - ((20(81div9))/25)$ ?

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Answer 1 · 2016-10-20T17:01:06

$- 7$ $-7$

= $\frac{1}{5} - (20 \times \frac{(81 \div 9)}{25})$ $1/5 - (20xx color(red)((81 -: 9))/ 25)$

Solve the inner bracket, $81 \div 9 = 9$ $color(blue)(81 -: 9 = 9)$ , so

= $\frac{1}{5} - (\frac{(20 \times 9)}{25})$ $1/5 - (((20xxcolor(blue)9))/ 25)$

Solve $20 \times 9 = 180$ $color(brown)(20xx 9= 180)$

= $\frac{5}{25} - \frac{180}{25}$ $5/25- 180/25$

= $\frac{5 - 180}{25}$ $(5-180)/25$

= $- \frac{175}{25}$ $-175/25$

= $- 7$ $-7$

How do you find the value of 15−(20(81÷9)25)1/5 - ((20(81div9))/25)?