How do you multiply $(4m ^ { - 6} n ^ { 10} ) ( - 10m ^ { - 2} n ^ { 3} )$ ?

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Answer 1 · 2016-11-05T06:39:58

By multiplying like terms.

So here you have $(4m^-6n^10)(-10m^-2n^3)$ .

Essentially you just add the exponents on the like terms (add the exponents on the m's and n's) and then multiply the constants.

$4*-10=-40$
$m^-6*m^-2=m^(-6+(-2))=m^-8$
$n^10*n^3=n^(10+3)=n^13$

Put this all together and you get

$-40m^-8n^13$

To make it look prettier you could say

$(-40n^13)/m^8$

How do you multiply (4m ^ { - 6} n ^ { 10} ) ( - 10m ^ { - 2} n ^ { 3} )(4m ^ { - 6} n ^ { 10} ) ( - 10m ^ { - 2} n ^ { 3} )?