How do you differentiate y=(sin1(5x2))3?

1 Answer
Nov 6, 2016

dydx=30x(arcsin(5x2))215x2

Explanation:

The derivative of arcsin(u) (or sin1(u)) is 11u2dudx

So by using the chain rule,
dydx=3(arcsin(5x2))2115x210x

Which can be simplified to:
dydx=30x(arcsin(5x2))215x2