How many solutions does $x^{2} - 6 = 0$ $x^2-6=0$ have?

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How many solutions does $x^{2} - 6 = 0$ $x^2-6=0$ have?

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Answer 1 · 2016-11-13T20:27:16

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Explanation:

$x^{2} - 6 = 0$ $x^2 - 6 = 0$

$x^{2} = 6$ $x^2 = 6$

$x = \sqrt{6}$ $x = sqrt(6)$ or $x = - \sqrt{6}$ $x = -sqrt(6)$

This is because $(- \sqrt{6}) \times (- \sqrt{6})$ $(-sqrt(6)) xx (-sqrt(6))$ is also $6$ $6$ because two negatives multiplied together make a positive.

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How many solutions does $x^{2} - 6 = 0$ $x^2-6=0$ have?

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How many solutions does $x^{2} - 6 = 0$ $x^2-6=0$ have?