How do you solve $\frac { b + 6} { b - 3} = 2$ ?

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Answer 1 · 2016-11-15T02:59:17

$b=12$

Multiply both sides by $b-3$ .

$b+6=2(b-3)$

Distribute the 2

$b+6=2b-6$

Add $6$ to both sides

$b+12=2b$

Subtract $b$ from both sides

$12=b$

How do you solve \frac { b + 6} { b - 3} = 2\frac { b + 6} { b - 3} = 2?