How do you find the center and radius of the circle given $(x-3)^2+(y+7)^2=50$ ?

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Answer 1 · 2016-12-04T04:01:39

The center is $(3,-7)$ and the radius is $5sqrt2$ .

Find the center and radius of $(x-3)^2 + (y+7)^2=50$

The equation of a circle is $(x-h)^2 +(y-k)^2=r^2$

where $(h,k)=$ the center and $r=$ the radius.

$=> (h,k)=(3, -7)$ (note that the signs are opposite of the signs inside the parentheses)

$r^2=50$

To find r, square root both sides

$sqrt(r^2)=sqrt50$

$r=sqrt(25*2)$

$r=5sqrt2$

How do you find the center and radius of the circle given (x-3)^2+(y+7)^2=50(x-3)^2+(y+7)^2=50?