How do you solve $\frac { 2} { 3} y + 13\geq - \frac { 4} { 7}$ ?

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Answer 1 · 2016-12-07T21:36:44

Isolate the y so that you have a statement about solutions for it.

$2/3y+13>=-4/7$

Step 1: subtract 13 from both sides
$2/3y>=-4/7-13$

Step 2: simplify the subtraction on the right
$2/3y>=-95/7$

Step 3: multiply both sides by the reciprocal of $2/3$
$y>=-285/14$

How do you solve \frac { 2} { 3} y + 13\geq - \frac { 4} { 7}\frac { 2} { 3} y + 13\geq - \frac { 4} { 7}?