How do you simplify $4.5 \times \frac{v}{5.8} + 2$ $4.5\times \frac{v}{5.8}+2$ ?

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Answer 1 · 2016-12-10T04:15:10

$\frac{45 v}{58} + 2$ $(45v)/58+2$

$\frac{4.5}{1} \times \frac{v}{58} + 2$ $4.5/1 xx v/58+2$

Fractions are simpler to work with

so $\frac{9}{2} \cdot (\frac{v}{\frac{29}{5}}) + 2$ $9/2*(v/(29/5))+2$ is equal to

$\frac{9}{2} \cdot \frac{5 v}{29} + 2$ $9/2*(5v)/29+2$ which is equal to

$\frac{45 v}{58} + 2$ $(45v)/58+2$

The answer is a "never-ending" or infinite recurring decimal so the fractional form is best.

How do you simplify 4.5\times \frac{v}{5.8}+24.5×v5.8+24.5\times \frac{v}{5.8}+2?