How do you solve #8( 2n - 5) = - 31+ 7n#?

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Answer 1 · 2016-12-16T02:10:54

#n=1#

First we need to distribute what's in the parenthesis first.

#8*2n=16n# and #8*-5=-40#

So the simplified version of the left side of the equation is #16n-40#

We now have an equation such as:

#16n-40=-31+7n=?#

Add #40# to both sides:

#16n=9+7n#

Simply subtract #7n# from both sides now:

#16n-7n=9n#

Now divide by #9# to isolate the variable and get the final answer:

#9/9=1#

Since the variable has been isolated, the final quotient:

Answer: #n=1#