How do you condense $3 log + 4 log y - 2 log z$ ?

Question

8739 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-12-17T02:41:22

$log ((x^3y^4)/z^2)$

Condense $3logx+4logy-2logz$

Note: I assumed there was a typo in the question and added an $x$ .

First, use the log rule $alogx=logx^a$

$logx^3+logy^4-logz^2$

Next, use the log rules

$loga +logb=log(ab)$ and $loga-logb=log(a/b)$

There is a somewhat silly expression for this rule: in the land of logs, addition is multiplication and subtraction is division.

$log ((x^3y^4)/z^2)$

How do you condense 3 log + 4 log y - 2 log z3 log + 4 log y - 2 log z?