Question

How do you solve `16- 2r = 3r + 1`?

Answer 1

`r = 3`

Explanation:

Isolate the `r` terms on one side of the equation and the constants on the other side of the equation while keeping the equation balanced:

`16 - 2r + 2r - 1 = 3r + 2r + 1 - 1`

`16 - 0 - 1 = 3r + 2r + 0`

Next combine like terms on each side of the equation:

`15 = (3 + 2)r`

`15 = 5r`

Now, solve for `r` while keeping the equation balanced:

`15/5 = (5r)/5`

`3 = (cancel(5)r)/cancel(5)`

`r = 3`

Answer 2

`3=r`

Explanation:

You have to remember that when you are solving an equation like this, you have to arrange all of the some term on one side and the numbers on the other. When you switch something from one side to the other, you have to switch the negative to positive and positive to negative
Then once you have all of the r's on one side and the numbers on the other, you can then divide inorder to isolate the r.

`16-1=3r+2r`
`15=5r`
`3=r`