How do you solve $6 c + 14 = 4 + 4 c$ $6c + 14= 4+ 4c$ ?

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Answer 1 · 2016-12-18T05:28:54

$c = - 5$ $c=-5$

step 1 : Simplify both sides of the equation.

$6 c + 14 = 4 c + 4$ $6c+14=4c+4$

Step 2: Subtract 4c from both sides.

$6 c + 14 - 4 c = 4 c + 4 - 4 c$ $6c+14−4c=4c+4−4c$

$2 c + 14 = 4$ $2c+14=4$

Step 3: Subtract 14 from both sides.

$2 c + 14 - 14 = 4 - 14$ $2c+14−14=4−14$

$2 c = - 10$ $2c=−10$

Step 4: Divide both sides by 2.

$\frac{2 c}{2} = - \frac{10}{2}$ $(2c)/2=-10/2$

$c = - 5$ $c=-5$

How do you solve 6c+14=4+4c6c + 14= 4+ 4c?