How do you solve $p - 2 = 5 p + 4 p - 8$ $p-2= 5p + 4p - 8$ ?

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Answer 1 · 2016-12-20T23:18:00

Combine like terms and isolate the variable.

Get all the terms with $p$ $p$ on the left side of the $=$ $=$ sign and everything else on the right.

$p - 5 p - 4 p = - 8 + 2$ $p - 5p - 4p = - 8 + 2$

combine like terms

$- 8 p = - 6$ $-8p = -6$

divide both side by $- 8$ $-8$ to get only $p$ $p$ on the left

$\frac{- 8 p}{- 8} = \frac{- 6}{- 8}$ $(-8p)/(-8) = (-6)/(-8)$

$p = \frac{6}{8}$ $p = 6/8$ (6/8 is positive because two negatives is a positive)

reduce to lowest terms

$p = \frac{3}{4}$ $p = 3/4$

How do you solve p−2=5p+4p−8p-2= 5p + 4p - 8?