How do you solve $\frac { - 1- 3x } { 4} - \frac { 2x + x } { 6} = \frac { 1} { 3}$ ?

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Answer 1 · 2016-12-26T05:08:26

$x=-7/15$

$frac(-1-3x)(4)-frac(2x+x)(6)=1/3$

Multiply the equation by the LCD 12.

$12*[frac(-1-3x)(4)-frac(2x+x)(6)=1/3]$

$12/4 * (-1-3x)-12/6*(2x+x)=12/3$

$3(-1-3x) -2(2x+x)=4$

$-3-9x-4x-2x=4$

$-15x-3=color(white)a4$
$color(white)(aaaaa)+3color(white)(a)+3$

$-15x=7$

$(-15x)/-15=7/-15$

$x=-7/15$

How do you solve \frac { - 1- 3x } { 4} - \frac { 2x + x } { 6} = \frac { 1} { 3}\frac { - 1- 3x } { 4} - \frac { 2x + x } { 6} = \frac { 1} { 3}?