How do you find the amplitude and period of $y = 4 sin θ$ $y=4sintheta$ ?

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How do you find the amplitude and period of $y = 4 sin θ$ $y=4sintheta$ ?

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Answer 1 · 2017-01-01T23:14:18

The amplitude is $4$ $4$ and the period is $2 π$ $2pi$ .

Explanation:

Find the amplitude and period of $y = 4 sin θ$ $y=color(red)4sintheta$ .

A sine function can be written as $y = A sin (B x - C) + D$ $y=Asin(Bx-C)+D$

where $A$ $A$ is the amplitude

$\frac{2 π}{B}$ $(2pi)/B$ is the period

$\frac{C}{B}$ $C/B$ is the phase shift and

$D$ $D$ is the vertical shift.

This example, $y = 4 sin θ$ $y=4sintheta$ , may be be written as
$y = 4 sin 1 θ$ $y=color(red)4sincolor(blue)1theta$ where
$A = 4$ $A=color(red)4$ and $B = 1$ $B=color(blue)1$

The amplitude is $4$ $color(red)4$ and the period is $\frac{2 π}{1} = 2 π$ $(2pi)/color(blue)1=2pi$ .

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How do you find the amplitude and period of $y = 4 sin θ$ $y=4sintheta$ ?

1 Answer

Explanation:

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Science

Math

Humanities

... and beyond

How do you find the amplitude and period of y=4sinθy=4sintheta?

1 Answer

Explanation:

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Impact of this question

How do you find the amplitude and period of $y = 4 sin θ$ $y=4sintheta$ ?