How do you evaluate $(10x ^ { 6} - 12x ^ { 5} + 18x ^ { 4} - 20x ^ { 3} ) \div ( 2x ^ { 7} )$ ?

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Answer 1 · 2017-01-02T12:08:11

$5x^-1-6x^-2+9x^-3-10x^-4$

$(10x^6-12x^5+18x^4-20x^3)-:(2x^7)$

by long division:

$(10x^6-12^5+18x^4-20x^3)/(2x^7)$

$=5x^-1-6x^-2+9x^-3-10x^-4$

check:

$2x^7(5x^-1-6x^-2+9x^-3-10x^-4)$

$=(10x^(-1+7)-12x^(-2+7)+18x^(-3+7)-20x^(-4+7))$

$=(10x^6-12x^5+18x^4-20x^3)$

Take note: $a^3*a^4=a^(3+4)$ and $a^m/a^n=a^(m-n)$ $m>n$

How do you evaluate (10x ^ { 6} - 12x ^ { 5} + 18x ^ { 4} - 20x ^ { 3} ) \div ( 2x ^ { 7} )(10x ^ { 6} - 12x ^ { 5} + 18x ^ { 4} - 20x ^ { 3} ) \div ( 2x ^ { 7} )?