Question

Question #e7c45

Answer 1

Please see explanation below.

Explanation:

Rewrite everything in terms of `sin(x)` and `cos(x)`

`(1/cosx)/((sinx/cosx)+(cosx/sinx))=sinx`

rewrite denominator

`(1/cosx)/((sin^2x+cos^2x)/(cosxsinx))=sinx`

Note that `sin^2x+cos^2x=1`

`(1/cosx)/(1/(cosxsinx))=sinx`

We rewrite the fraction as follows

`(1/cosx)(cosxsinx)/1`

The `cosx` cancels and we are left with

`sinx=sinx`