How do you solve 3x2+7x13=0?

1 Answer
Jan 22, 2017

x=7+2056 and x=72056

Explanation:

This is a quadratic equation with respect to x. We will use the quadratic formula:

For an equation of the type
ax2+bx+c=0,a0

x=b±b24ac2a
Putting our values in the equation:

x=7±(7)24(3)(13)2(3)
x=7±49+1566

x=7±2056