A circular rug has a radius of $(4x-6)$ . What is the area of the rug?

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Answer 1 · 2017-01-28T02:40:37

$A=16pix^2-48pix+36pi$

Remember the area of a circle's formula is
$A=pir^2$

In this case $r=(4x-6) => r^2=(4x-6)^2=(4x-6)(4x-6)$

Then using FOIL we get

$r^2=(4x-6)^2=16x^2-48x+36$

Then the area of the rug $A$ is

$A=pir^2=16pix^2-48pix+36pi$

A circular rug has a radius of (4x-6)(4x-6). What is the area of the rug?