Question

A circular rug has a radius of `(4x-6)`. What is the area of the rug?

Answer 1

`A=16pix^2-48pix+36pi`

Explanation:

Remember the area of a circle's formula is
`A=pir^2`

In this case `r=(4x-6) => r^2=(4x-6)^2=(4x-6)(4x-6)`

Then using FOIL we get

`r^2=(4x-6)^2=16x^2-48x+36`

Then the area of the rug `A` is

`A=pir^2=16pix^2-48pix+36pi`