How do you solve $\frac{5 x}{3} + \frac{9}{8} = \frac{7 x}{6} + \frac{3}{16}$ $\frac { 5x } { 3} + \frac { 9} { 8} = \frac { 7x} { 6} + \frac { 3} { 16}$ ?

Question

1211 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-01-28T18:17:12

$x = - 1 \frac{7}{8} or - 1.875$ $x=-1 7/8 or -1.875$

$\frac{5 x}{3} + \frac{9}{8} = \frac{7 x}{6} + \frac{3}{16}$ $(5x)/3+9/8=(7x)/6+3/16$

$:.(80x+54=56x+9)/48$

$:.(80x)/48+54/48=(56x)/48+9/48$

$:.80x+54=56x+9$

$:.80x-56x=9-54$

$:.24x=-45$

divide both sides by 3

$:.8x=-15$

$:.x=-15/8$

$:.x=-1 7/8or -1.875$

check:

substitute $x= -1.875$

$:.5(-1.875/3)+1.125=7(-1.875)/6+0.1875$

$:.5(-0.625)+1.125=-2.1875+0.1875$

$:.-3.125+1.125=-2.1875+0.1875$

$:.-2=-2$

How do you solve \frac { 5x } { 3} + \frac { 9} { 8} = \frac { 7x} { 6} + \frac { 3} { 16}5x3+98=7x6+316\frac { 5x } { 3} + \frac { 9} { 8} = \frac { 7x} { 6} + \frac { 3} { 16}?