How do you solve 3(x+3)=4x3(x+3)=4x?

1 Answer
Jan 29, 2017

color(blue)(x=9)x=9

Explanation:

3(x+3)=4x3(x+3)=4x

Using distributive property to evaluate the expression in the left side of the equation,

3x+9=4x3x+9=4x

transposing +9+9 to the other side of the equation, by grouping all the same expression or term, it is a standard that the unknown variable must be in the left side of the equation,

Subtracting 99 from both sides,

3x+9-9=4x-93x+99=4x9

Refining the equation,

3x=4x-93x=4x9

now we must move the 4x4x to the left, balance it by subtracting both sides by 4x4x,

3x-4x=4x-9-4x3x4x=4x94x

Refining the equation again, we get,

-x=-9x=9

but, xx, the unknown variable must be positive, therefore we need to take off it's negativity, since -x = -1(x)x=1(x)

cancel(-x)/cancel(-1)=(-9)/-1

therefore, the answer is,

color(blue)(x=9)