How do you solve #\frac { x + 5} { 2} + 3= x - 2#?

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Answer 1 · 2017-02-02T15:46:31

#x=15#

#(x+5)/2+3=x-2#

multiply both sides by 2

#:.x+5+6=2(x-2)#

#:.x+11=2x-4#

#:.x-2x=-11-4#

#:.-x=-15#

multiply both sides by# -1#

#:.x=15#

substitute #x=15#

#:.(15+5)/2+3=15-2#

#:.20/2+3=13#

#:.10+3=13#

#:.13=13#