How do you differentiate $y=ln(x^2)$ ?

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Answer 1 · 2017-02-02T20:27:01

The derivative is $dy/dx=2/x$

As with some problems involving differentiation of logarithmic functions, this problem can be simplified using the laws of logarithms.

$y=ln(x^2)$
$y=2lnx$
$dy/dx=2*1/x=2/x$

How do you differentiate y=ln(x^2)y=ln(x^2)?