How do you solve #4x ^ { 2/ 3} - 5= 103#?

1 Answer
Priscilla Y.
Feb 5, 2017

x #~~#140.3

Explanation:

You first want to start off by isolating the variable "x." Add 5 to both sides and get: #4x^(2/3)# = 108. Then further isolate the variable by dividing both sides by 4, and get: #x^(2/3)# = 27. Lastly, raise both sides by the reciprocal of 2/3, which is 3/2. This would multiply the exponents, (2/3)(3/2), which is 1. This leaves x = #27^(2/3)#, which is also x #~~#140.3

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