How do you simplify $\frac{21 m^{- 9} n^{9}}{28 m^{- 2} n^{- 4}}$ $\frac { 21m ^ { - 9} n ^ { 9} } { 28m ^ { - 2} n ^ { - 4} }$ ?

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Answer 1 · 2017-02-23T12:05:30

$\frac{3 n^{13}}{4 m^{7}}$ $\frac{3n^13}{4m^7}$

First, you have to rewrite the equation by using this rule:
$a^{- b} = \frac{1}{a^{b}}$ $a^-b=\frac{1}{a^b}$

$\frac{\frac{21 n^{9}}{m^{9}}}{\frac{28}{m^{2} n^{4}}}$ $\frac{\frac{21n^9}{m^9}}{\frac{28}{m^2n^4}}$

And then simplify that fraction by I call "the numerator times the denominator, the denominator times the numerator"

$\frac{21 n^{9} \times m^{2} n^{4}}{m^{9} \times 28}$ $\frac{21n^9\timesm^2n^4}{m^9\times28}$

and simplify this one again:

$\frac{3 n^{13}}{4 m^{7}}$ $\frac{3n^13}{4m^7}$

How do you simplify \frac { 21m ^ { - 9} n ^ { 9} } { 28m ^ { - 2} n ^ { - 4} }21m−9n928m−2n−4\frac { 21m ^ { - 9} n ^ { 9} } { 28m ^ { - 2} n ^ { - 4} }?