Question

How do you integrate `7/(2x-3)` using partial fractions?

Answer 1

You don't need to

Explanation:

This is already in a partial fraction form

`int 7/(2x-3) dx`

`7/2 int 2/(2x-3) dx`

`7/2 ln|2x-3|`

You only need to use partial fractions when there are multiple (x-k) (or quadratic) terms in the denominator, or the expression is factorable.