Question

A1.00 kg rubber stopper is swung horizontally at the end of a cord 1.50 m long at the rate of 2.00 m/s. What is the centripetal acceleration?

Answer 1

`=8/3` `m/s^2`

Explanation:

`a_c = v^2/r`

Where `a_c` is acceleration, `v` is velocity and `r` is radius

`v^2/r`
`=4/1.5`
`=8/3` `m/s^2`