The sum of the digits of a two-digit number is 11. The tens digit is one less than three times the ones digit. What is the original number?

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Answer 1 · 2017-03-10T05:29:25

Number = 83

Let the number in unit place be $x$ & the number in tens place be $y$ .

According to the first condition,

$x+y=11$

According to the second condition,

$x=3y-1$

Solving two simultaneous equation for two variable:

$3y-1+y=11$

$4y-1=11$

$4y=12$

$y=3$

$x=8$

The original number is $83$