Question

How do you evaluate `58.3 times .13`?

Answer 1

`rArr7.579`

Explanation:

`58.3 xx .13`

`rArr58.3 xx 0.13`

`rArr7.579`

Answer 2

`7.579`

Explanation:

`color(red)(" A different type of approach")`

If the decimal places are giving you a problem this is another way of approaching it.

`58.3` is the same as `583xx1/10`

`0.13` is the same as `13xx1/100`

So `58.3xx0.13` is the same as:

`583xx13xx1/10xx1/100`

`583xx13xx1/1000`

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
`color(blue)("Dealing with "583xx13" part")`

13 can be split into `10+3`

`10xx583->5830`
`color(white)(1)3xx583->ul( 1749) larr" add"`
`" "7579`
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
`color(blue)("Dealing with "xx1/1000" part")`

`7579xx1/1000 = 7.579`