How do you solve $3 - 4 x \geq 27$ $3- 4x \geq 27$ ?

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Answer 1 · 2017-03-18T15:30:21

$x \leq - 6$ $x<=-6$

The given inequality is equivalent to:

$- 4 x \geq 27 - 3$ $-4x>=27-3$

$- 4 x \geq 24$ $-4x>=24$

You would change signs and direction:

$4 x \leq - 24$ $4x<=-24$

$x \leq - \frac{24}{4}$ $x<=-24/4$

$x \leq - 6$ $x<=-6$

How do you solve 3−4x≥273- 4x \geq 27?