Question

How do you factor `81p ^ { 2} + 108p + 36`?

Answer 1

`(9p+6)^2`

Explanation:

Since

`81p^2=(9p)^2`

and

`36=6^2`

and

`108p=2*9p*6`,

then the given polynomial is the expanded square of the bynomial `9p+6`:

`(9p+6)^2`